Integrand size = 21, antiderivative size = 410 \[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )}+\frac {c e^2 \left (3 c d^2-a e^2\right ) x \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2 n},\frac {1}{2} \left (2+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^3}-\frac {c \left (c d^2-a e^2\right ) (1-2 n) x \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2 n},\frac {1}{2} \left (2+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^2 n}+\frac {4 c e^4 x \operatorname {Hypergeometric2F1}\left (1,\frac {1}{n},1+\frac {1}{n},-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^3}-\frac {4 c^2 d e^3 x^{1+n} \operatorname {Hypergeometric2F1}\left (1,\frac {1+n}{2 n},\frac {1}{2} \left (3+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^3 (1+n)}+\frac {c^2 d e (1-n) x^{1+n} \operatorname {Hypergeometric2F1}\left (1,\frac {1+n}{2 n},\frac {1}{2} \left (3+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^2 n (1+n)}+\frac {e^4 x \operatorname {Hypergeometric2F1}\left (2,\frac {1}{n},1+\frac {1}{n},-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^2} \]
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Time = 0.26 (sec) , antiderivative size = 410, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {1451, 251, 1445, 1432, 371} \[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\frac {c^2 d e (1-n) x^{n+1} \operatorname {Hypergeometric2F1}\left (1,\frac {n+1}{2 n},\frac {1}{2} \left (3+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a^2 n (n+1) \left (a e^2+c d^2\right )^2}-\frac {c (1-2 n) x \left (c d^2-a e^2\right ) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2 n},\frac {1}{2} \left (2+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{2 a^2 n \left (a e^2+c d^2\right )^2}-\frac {4 c^2 d e^3 x^{n+1} \operatorname {Hypergeometric2F1}\left (1,\frac {n+1}{2 n},\frac {1}{2} \left (3+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a (n+1) \left (a e^2+c d^2\right )^3}+\frac {c e^2 x \left (3 c d^2-a e^2\right ) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2 n},\frac {1}{2} \left (2+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a \left (a e^2+c d^2\right )^3}+\frac {c x \left (-a e^2+c d^2-2 c d e x^n\right )}{2 a n \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )}+\frac {4 c e^4 x \operatorname {Hypergeometric2F1}\left (1,\frac {1}{n},1+\frac {1}{n},-\frac {e x^n}{d}\right )}{\left (a e^2+c d^2\right )^3}+\frac {e^4 x \operatorname {Hypergeometric2F1}\left (2,\frac {1}{n},1+\frac {1}{n},-\frac {e x^n}{d}\right )}{d^2 \left (a e^2+c d^2\right )^2} \]
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Rule 251
Rule 371
Rule 1432
Rule 1445
Rule 1451
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {e^4}{\left (c d^2+a e^2\right )^2 \left (d+e x^n\right )^2}+\frac {4 c d e^4}{\left (c d^2+a e^2\right )^3 \left (d+e x^n\right )}-\frac {c \left (-c d^2+a e^2+2 c d e x^n\right )}{\left (c d^2+a e^2\right )^2 \left (a+c x^{2 n}\right )^2}-\frac {c e^2 \left (-3 c d^2+a e^2+4 c d e x^n\right )}{\left (c d^2+a e^2\right )^3 \left (a+c x^{2 n}\right )}\right ) \, dx \\ & = -\frac {\left (c e^2\right ) \int \frac {-3 c d^2+a e^2+4 c d e x^n}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^3}+\frac {\left (4 c d e^4\right ) \int \frac {1}{d+e x^n} \, dx}{\left (c d^2+a e^2\right )^3}-\frac {c \int \frac {-c d^2+a e^2+2 c d e x^n}{\left (a+c x^{2 n}\right )^2} \, dx}{\left (c d^2+a e^2\right )^2}+\frac {e^4 \int \frac {1}{\left (d+e x^n\right )^2} \, dx}{\left (c d^2+a e^2\right )^2} \\ & = \frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )}+\frac {4 c e^4 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^3}+\frac {e^4 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^2}-\frac {\left (4 c^2 d e^3\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^3}+\frac {\left (c e^2 \left (3 c d^2-a e^2\right )\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^3}+\frac {c \int \frac {\left (-c d^2+a e^2\right ) (1-2 n)+2 c d e (1-n) x^n}{a+c x^{2 n}} \, dx}{2 a \left (c d^2+a e^2\right )^2 n} \\ & = \frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )}+\frac {c e^2 \left (3 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^3}+\frac {4 c e^4 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^3}-\frac {4 c^2 d e^3 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^3 (1+n)}+\frac {e^4 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^2}-\frac {\left (c \left (c d^2-a e^2\right ) (1-2 n)\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{2 a \left (c d^2+a e^2\right )^2 n}+\frac {\left (c^2 d e (1-n)\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{a \left (c d^2+a e^2\right )^2 n} \\ & = \frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )}+\frac {c e^2 \left (3 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^3}-\frac {c \left (c d^2-a e^2\right ) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^2 n}+\frac {4 c e^4 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^3}-\frac {4 c^2 d e^3 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^3 (1+n)}+\frac {c^2 d e (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^2 n (1+n)}+\frac {e^4 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^2} \\ \end{align*}
Time = 0.47 (sec) , antiderivative size = 298, normalized size of antiderivative = 0.73 \[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\frac {x \left (\frac {c e^2 \left (3 c d^2-a e^2\right ) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2 n},\frac {1}{2} \left (2+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a}+4 c e^4 \operatorname {Hypergeometric2F1}\left (1,\frac {1}{n},1+\frac {1}{n},-\frac {e x^n}{d}\right )-\frac {4 c^2 d e^3 x^n \operatorname {Hypergeometric2F1}\left (1,\frac {1+n}{2 n},\frac {1}{2} \left (3+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a (1+n)}+\frac {c \left (c d^2-a e^2\right ) \left (c d^2+a e^2\right ) \operatorname {Hypergeometric2F1}\left (2,\frac {1}{2 n},\frac {1}{2} \left (2+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a^2}+\frac {e^4 \left (c d^2+a e^2\right ) \operatorname {Hypergeometric2F1}\left (2,\frac {1}{n},1+\frac {1}{n},-\frac {e x^n}{d}\right )}{d^2}-\frac {2 c^2 d e \left (c d^2+a e^2\right ) x^n \operatorname {Hypergeometric2F1}\left (2,\frac {1+n}{2 n},\frac {1}{2} \left (3+\frac {1}{n}\right ),-\frac {c x^{2 n}}{a}\right )}{a^2 (1+n)}\right )}{\left (c d^2+a e^2\right )^3} \]
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\[\int \frac {1}{\left (d +e \,x^{n}\right )^{2} \left (a +c \,x^{2 n}\right )^{2}}d x\]
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\[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\int { \frac {1}{{\left (c x^{2 \, n} + a\right )}^{2} {\left (e x^{n} + d\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\text {Timed out} \]
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\[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\int { \frac {1}{{\left (c x^{2 \, n} + a\right )}^{2} {\left (e x^{n} + d\right )}^{2}} \,d x } \]
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\[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\int { \frac {1}{{\left (c x^{2 \, n} + a\right )}^{2} {\left (e x^{n} + d\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^2} \, dx=\int \frac {1}{{\left (a+c\,x^{2\,n}\right )}^2\,{\left (d+e\,x^n\right )}^2} \,d x \]
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